In CBSE Class 10 Science Paper, Students will have to answer some questions based on Assertion and Reason. There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given.
Here we are providing you with Class 10 Science Chapter 12 Electricity Case Study Questions, by practicing these Case Study and Passage Based Questions will help you in your Class 10th Board Exam.
Case Study Chapter 12 Electricity
Here, we have provided case-based/passage-based questions for Class 10 Science Chapter 12 Electricity
Case Study/Passage Based Questions
The heating effect of current is obtained by the transformation of electrical energy into heat energy. Just as mechanical energy used to overcome friction is covered into heat, in the same way, electrical energy is converted into heat energy when an electric current flows through a resistance wire. The heat produced in a conductor, when a current flows through it is found to depend directly on (a) strength of current (b) resistance of the conductor (c) time for which the current flows.
The mathematical expression is given by H = I2Rt.
The electrical fuse, electrical heater, electric iron, electric geyser, etc. all are based on the heating effect of current.
(i) What are the properties of heating elements?
(a) High resistance, high melting point
(b) Low resistance, high melting point
(c) Low resistance, high melting point
(d) Low resistance, low melting point.
Answer: (b) Low resistance, high melting point
(ii) What are the properties of an electric fuse?
(a) Low resistance, low melting point
(b) High resistance, high melting point.
(c) High resistance, low melting point
(d) Low resistance, high melting point
Answer: (c) High resistance, low melting point
(iii) When the current is doubled in a heating device and time is halved, the heat energy produced is
|(a) doubled||(b) halved|
|(c) four times||(d) one fourth times|
Answer: (a) doubled
(iv) A fuse wire melts at 5 A. It is is desired that the fuse wire of same material melt at 10 A. The new radius of the wire is
|(a) 4 times||(b) 2 times|
|(c) 6 times||(d) 8 times|
Answer: (b) 2 times
(v) When a current of 0.5 A passes through a conductor for 5 min and the resistance of conductor is 10 ohm, the amount of heat produced is
|(a) 250 J||(b) 5000J|
|(c) 750J||(d) 1000J|
Answer: (c) 750J
The relationship between potential difference and the current was first established by George Simon Ohm. This relationship is known as Ohm’s law. According to this law, the current passed through a conductor is proportional to the potential difference applied between its ends provided the temperature remains constant i.e. I ∝ V or V = IR where R is the constant for the conductor and it is known as the resistance of the conductor. Although Ohm’s law has been found valid over a large class of materials, there are some materials that do not hold Ohm’s law.
2.1) Name the law which is illustrated by the VI graph.
(a) Lenz law
(b) Faraday’s law
(c) Ohm’s law
(d) Newton’s law
Answer(c) Ohm’s law
2.2) By increasing the voltage across a conductor, the
(a) current will decrease
(b) current will increase
(c) resistance will increase
(d) resistance will decrease
Answer(b) current will increase
2.3) When a battery of 9 V is connected across a conductor and the current flows is 0.1 A, the resistance is
(a) 9 Ohm
(b) 0.9 Ohm
(c) 90 Ohm
(d) 900 Ohm
Answer(c) 90 Ohm
2.4) If both the potential difference and resistance in a circuit are doubled then :
(a) current remains same
(b) current becomes double
(c) current becomes zero
(d) current becomes half
Answer(a) current remains same
2.5) Keeping the potential difference constant, the resistance of a circuit is doubled. The current will become :
(c) one fourth
(d) 4 time
You can also practice Class 10 Science MCQ Questions for Board Exams.