In Class 12 Boards there will be Case studies and Passage Based Questions will be asked, So practice these types of questions. Study Rate is always there to help you. Free PDF Download of CBSE Class 12 Physics Chapter 4 Moving Charges and Magnetism Case Study and Passage Based Questions with Answers were Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 12 Physics Moving Charges and Magnetism to know their preparation level.
In CBSE Class 12 Physics Paper, Students will have to answer some questions based on Assertion and Reason. There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.
Moving Charges and Magnetism Case Study Questions With answers
Here, we have provided case-based/passage-based questions for Class 12 Physics Chapter 4 Moving Charges and Magnetism
Case Study/Passage-Based Questions
A charged particle moving in a magnetic field experiences a force that is proportional to the strength of the magnetic field, the component of the velocity that is perpendicular to the magnetic field, and the charge of the particle.
This force is given by F⃗ =q(v⃗ ×B⃗ )F→=q(v→×B→) where q is the electric charge of the particle, v is the instantaneous velocity of the particle, and B is the magnetic field (in tesla).
The direction of force is determined by the rules of the cross product of two vectors
Force is perpendicular to both velocity and magnetic field. Its direction is the same as v⃗ ×B⃗ v→×B→ if q is positive and opposite of v⃗ ×B⃗ v→×B→ if q is negative
The force is always perpendicular to both the velocity of the particle and the magnetic field that created it. Because the magnetic force is always perpendicular to the motion, the magnetic field can do no work on an isolated charge. It can only do work indirectly, via the electric field generated by a changing magnetic field.
(I) When a magnetic field is applied to a stationary electron, it
|(a) remains stationary|
|(b) spins about its own axis|
|(c) moves in the direction of the field|
|(d) moves perpendicular to the direction of the field.|
Answer: (a) remains stationary
(ii) A proton is projected with a uniform velocity v along the axis of a current carrying solenoid, then
|(a) the proton will be accelerated along the axis|
|(b) the proton path will be circular about the axis|
|(c) the proton moves along a helical path|
|(d) the proton will continue to move with velocity v along the axis.|
Answer: (d) the proton will continue to move with velocity v along the axis.
(iii) A charged particle experiences a magnetic force in the presence of the magnetic field. Which of the following statement is correct?
|(a) The particle is stationary and the magnetic field is perpendicular.|
|(b) The particle is moving and the magnetic field is perpendicular to the velocity|
|(c) The particle is stationary and the magnetic field is parallel|
|(d) The particle is moving and the magnetic field is parallel to the velocity|
Answer: (b) The particle is moving and the magnetic field is perpendicular to the velocity
(iv) A charge q moves with a velocity 2 ms-1 along the x-axis in a uniform magnetic field B⃗ =(i^+2j^+3k^)TB→=(i^+2j^+3k^)T then a charge will experience a force
|(a) in z-y plane||(b) along -yaxis||(c) along +z axis||(d) along -z axis|
Answer: (a) in z-y plane
(v) Moving charge will produce
|(a) electric field only||(b) magnetic field only|
|(c) both electric and magnetic field||(d) none of these.|
Answer: (c) both electric and magnetic field
Moving coil galvanometer operates on Permanent Magnet Moving Coil (PMMC) mechanism and was designed by the scientist D’arsonval.
Moving coil galvanometers are of two types
(i) Suspended coil
(ii) Pivoted coil type or tangent galvanometer.
Its working is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque. This torque tends to rotate the coil about its axis of suspension in such a way that the magnetic flux passing through the coil is maximum.
(i) A moving coil galvanometer is an instrument which
|(a) is used to measure emf|
|(b) is used to measure potential difference|
|(c) is used to measure resistance|
|(d) is a deflection instrument that gives a deflection when a current flows through its coil|
Answer: (d) is a deflection instrument that gives a deflection when a current flows through its coil
(ii) To make the field radial in a moving coil galvanometer
|(a) number of turns of the coil is kept small||(b) magnet is taken in the form of horse-shoe|
|(c) poles are of very strong magnets||(d) poles are cylindrically cut|
Answer: (d) poles are cylindrically cut
(iii) The deflection in a moving coil galvanometer is
|(a) directly proportional to the torsional constant of spring|
|(b) directly proportional to the number of turns in the coil|
|(c) inversely proportional to the area of the coil|
|(d) inversely proportional to the current in the coil|
Answer: (b) directly proportional to the number of turns in the coils
(iv) In a moving coil galvanometer, having a coil of N-turns of area A and carrying current I is placed in a radial field of strength B.
The torque acting on the coil is
|(a) NA2B2I||(b) NABI2||(c) N2ABI||(d) NABI|
Answer: (d) NABI
(v) To increase the current sensitivity of a moving coil galvanometer, we should decrease
|(a) strength of magnet||(b) the torsional constant of spring|
|(c) number of turns in the coil||(d) area of coil|
Answer: (b) the torsional constant of spring
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